How can I remove all instances of an element from a list in Python? [duplicate]

Answer 1

filter([1,1].__ne__,a)

Answer 2

If you want to modify the list in-place,

a[:] = [x for x in a if x != [1, 1]]

Answer 3

new_list = filter(lambda x: x != [1,1], a)

Or as a function:

def remove_all(element, list):
    return filter(lambda x: x != element, list)

a = remove([1,1],a)

Or more general:

def remove_all(elements, list):
    return filter(lambda x: x not in elements, list)

a = remove(([1,1],),a)

Answer 4

Use a list comprehension:

[x for x in a if x != [1, 1]]

Answer 5

Here is an easier alternative to Alex Martelli's answer:

a = [x for x in a if x != [1,1]]

Answer 6

Google finds Delete all items in the list, which includes gems such as

from functools import partial
from operator import ne
a = filter(partial(ne, [1, 1]), a)