Returning a regex match in VBA (excel)

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别跟我提以往
别跟我提以往 2020-11-27 02:41

I am trying to write a function for excel 2010 that will take a cell of unstructured text, look for something called an sdi value and, if found, return that number. The sdi

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  • 2020-11-27 03:07

    You need to access the matches in order to get at the SDI number. Here is a function that will do it (assuming there is only 1 SDI number per cell).

    For the regex, I used "sdi followed by a space and one or more numbers". You had "sdi followed by a space and zero or more numbers". You can simply change the + to * in my pattern to go back to what you had.

    Function ExtractSDI(ByVal text As String) As String
    
    Dim result As String
    Dim allMatches As Object
    Dim RE As Object
    Set RE = CreateObject("vbscript.regexp")
    
    RE.pattern = "(sdi \d+)"
    RE.Global = True
    RE.IgnoreCase = True
    Set allMatches = RE.Execute(text)
    
    If allMatches.count <> 0 Then
        result = allMatches.Item(0).submatches.Item(0)
    End If
    
    ExtractSDI = result
    
    End Function
    

    If a cell may have more than one SDI number you want to extract, here is my RegexExtract function. You can pass in a third paramter to seperate each match (like comma-seperate them), and you manually enter the pattern in the actual function call:

    Ex) =RegexExtract(A1, "(sdi \d+)", ", ")
    

    Here is:

    Function RegexExtract(ByVal text As String, _
                          ByVal extract_what As String, _
                          Optional seperator As String = "") As String
    
    Dim i As Long, j As Long
    Dim result As String
    Dim allMatches As Object
    Dim RE As Object
    Set RE = CreateObject("vbscript.regexp")
    
    RE.pattern = extract_what
    RE.Global = True
    Set allMatches = RE.Execute(text)
    
    For i = 0 To allMatches.count - 1
        For j = 0 To allMatches.Item(i).submatches.count - 1
            result = result & seperator & allMatches.Item(i).submatches.Item(j)
        Next
    Next
    
    If Len(result) <> 0 Then
        result = Right(result, Len(result) - Len(seperator))
    End If
    
    RegexExtract = result
    
    End Function
    

    *Please note that I have taken "RE.IgnoreCase = True" out of my RegexExtract, but you could add it back in, or even add it as an optional 4th parameter if you like.

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