How to wait until jQuery ajax request finishes in a loop?

Question

I have that code :

for (var i = 0; i < $total_files; i++) {
  $.ajax({
    type: \'POST\',
    url: \'uploading.php\',
    context: $(this),
    dataType:         


        

Answer 1

You can create an array of promises so that once all promises are resolved you can run your all done code.

var promises = [];
for (var i = 0; i < $total_files; i++){ 
   /* $.ajax returns a promise*/      
   var request = $.ajax({
        /* your ajax config*/
   })

   promises.push( request);
}

$.when.apply(null, promises).done(function(){
   alert('All done')
})

DEMO

Answer 2

I would try jQuery.when so you can still use asynchronous call but deferred, something like :

jQuery(document).ready(function ($) {
    $.when(
        //for (var i = 0; i < $total_files; i++) {
            $.ajax({
                // ajax code
            })
        //}
    ).done(function () {
        // perform after ajax loop is done
    }); 
}); // ready

EDIT : ajax iteration should be done outside $.when and pushed into an array as proposed by charlietfl's answer. You may use an (asynchronous) ajax call and defer it inside $.when though, see JSFIDDLE

Answer 3

In one statement with jquery

$.when.apply(null, $.map(/*input Array|jQuery*/, function (n, i) {
   return $.get(/* URL */, function (data) {
     /* Do something */
   });
})).done(function () {
  /* Called after all ajax is done  */
});

Answer 4

For jQuery 3.x+ and modern browser that support native Promise, Promise.all could be used this way:

var promises = [];
for (var i = 0; i < $total_files; i++) {
   // jQuery returns a prom 
   promises.push($.ajax({
      /* your ajax config*/
   }))
}

Promise.all(promises)
.then(responseList => {
   console.dir(responseList)
})

If your files are already stored in a list then you could use map instead of a loop.

var fileList = [/*... list of files ...*/];

Promise.all(fileList.map(file => $.ajax({
      /* your ajax config*/
})))
.then(responseList => {
   console.dir(responseList)
})

Answer 5

Populate an array with each call and call the next item when the previous is done.

You could try something like that:

    window.syncUpload = {

        queue : [],

        upload : function(imagesCount) {

            var $total_files = imagesCount, data_string = "";

            /* Populates queue array with all ajax calls you are going to need */
            for (var i=0; i < $total_files; i++) {       
                this.queue.push({
                    type: 'POST',
                    url: 'uploading.php',
                    context: $(this),
                    dataType: 'json',
                    cache: false,
                    contentType: false,
                    processData: false,
                    data: data_string,
                    success: function(datas) {
                    //does something
                    },
                    error: function(e){
                        alert('error, try again');
                    },
                    /* When the ajax finished it'll fire the complete event, so we
                       call the next image to be uploaded.
                    */
                    complete : function() {
                        this[0].uploadNext();
                    }
                });
            }

            this.uploadNext();
        },

        uploadNext : function() {
            var queue = this.queue;

            /* If there's something left in the array, send it */
            if (queue.length > 0) {
                /* Create ajax call and remove item from array */
                $.ajax(queue.shift(0));
            }


        }

    }

Just call it using syncUpload.upload(NUMBER_OF_IMAGES);