Replace array entry with spread syntax in one line of code?

Question

I\'m replacing an item in a react state array by using the ... spread syntax. This works:

let newImages = [...this.state.images]
newImages[4] = updatedImage
this         


        

Answer 1

use Array.slice

this.setState({images: [...this.state.images.slice(0, 3), updatedImage, ...this.state.images.slice(4)]})

Answer 2

You can use map:

const newImages = this.state.images
  .map((image, index) => index === 4 ? updatedImage : image)

Answer 3

You can convert the array to objects (the ...array1), replace the item (the [1]:"seven"), then convert it back to an array (Object.values) :

array1 = ["one", "two", "three"];
array2 = Object.values({...array1, [1]:"seven"});
console.log(array1);
console.log(array2);

Answer 4

Object.assign does the job:

this.setState({images: Object.assign([], this.state.images, {4: updatedImage}));

...but involves a temporary object (the one at the end). Still, just the one temp object... If you do this with slice and spreading out arrays, it involve several more temporary objects (the two arrays from slice, the iterators for them, the result objects created by calling the iterator's next function [inside the ... handle], etc.).

It works because normal JS arrays aren't really arrays¹ (this is subject to optimization, of course), they're objects with some special features. Their "indexes" are actually property names meeting certain criteria². So there, we're spreading out this.state.images into a new array, passing that into Object.assign as the target, and giving Object.assign an object with a property named "4" (yes, it ends up being a string but we're allowed to write it as a number) with the value we want to update.

Live Example:

const a = [0, 1, 2, 3, 4, 5, 6, 7];
const b = Object.assign([], a, {4: "four"});
console.log(b);

If the 4 can be variable, that's fine, you can use a computed property name (new in ES2015):

let n = 4;
this.setState({images: Object.assign([], this.state.images, {[n]: updatedImage}));

Note the [] around n.

Live Example:

const a = [0, 1, 2, 3, 4, 5, 6, 7];
const index = 4;
const b = Object.assign([], a, {[index]: "four"});
console.log(b);

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¹ Disclosure: That's a post on my anemic little blog.

² It's the second paragraph after the bullet list:

An integer index is a String-valued property key that is a canonical numeric String (see 7.1.16) and whose numeric value is either +0 or a positive integer ≤ 2⁵³-1. An array index is an integer index whose numeric value i is in the range +0 ≤ i < 2³²-1.

So that Object.assign does the same thing as your create-the-array-then-update-index-4.

Answer 5

Here is my self explaning non-one-liner

 const wantedIndex = 4;
 const oldArray = state.posts; // example

 const updated = {
     ...oldArray[wantedIndex], 
     read: !oldArray[wantedIndex].read // attributes to change...
 } 

 const before = oldArray.slice(0, wantedIndex); 
 const after = oldArray.slice(wantedIndex + 1);

 const menu = [
     ...before,  
     updated,
     ...after
 ]

Answer 6

I refer to @Bardia Rastin solution, and I found that the solution has a mistake at the index value (it replaces item at index 3 but not 4).

If you want to replace the item which has index value, index, the answer should be

this.setState({images: [...this.state.images.slice(0, index), updatedImage, ...this.state.images.slice(index + 1)]})

this.state.images.slice(0, index) is a new array has items start from 0 to index - 1 (index is not included)

this.state.images.slice(index) is a new array has items starts from index and afterwards.

To correctly replace item at index 4, answer should be:

this.setState({images: [...this.state.images.slice(0, 4), updatedImage, ...this.state.images.slice(5)]})