How can I drop all indexes in a SQL database with one command?

Question

So, how can I drop all indexes in a SQL database with one command? I have this command that will get me all the 20 or so drop statements, but how can I run all of those drop s

Answer 1

From: Stephen Hill's Bloggie

DECLARE @indexName VARCHAR(128)
DECLARE @tableName VARCHAR(128)

DECLARE [indexes] CURSOR FOR

        SELECT          [sysindexes].[name] AS [Index],
                        [sysobjects].[name] AS [Table]

        FROM            [sysindexes]

        INNER JOIN      [sysobjects]
        ON              [sysindexes].[id] = [sysobjects].[id]

        WHERE           [sysindexes].[name] IS NOT NULL 
        AND             [sysobjects].[type] = 'U'
        --AND               [sysindexes].[indid] > 1

OPEN [indexes]

FETCH NEXT FROM [indexes] INTO @indexName, @tableName

WHILE @@FETCH_STATUS = 0
BEGIN
        --PRINT 'DROP INDEX [' + @indexName + '] ON [' + @tableName + ']'
        Exec ('DROP INDEX [' + @indexName + '] ON [' + @tableName + ']')

        FETCH NEXT FROM [indexes] INTO @indexName, @tableName
END

CLOSE           [indexes]
DEALLOCATE      [indexes]

GO