match first space on a line using sublime text and regular expressions

Question

So regular expressions have always been tough for me. Im getting frustrated trying to find a regular expression that will select the first white space on a line. So then i can u

Answer 1

In the spirit of @edi's answer, but with some explanation of what's happening. Match the beginning of the line with ^, then look for a sequence of characters that are not whitespace with [^\s]* or \S* (the former may work in more editors, libraries, etc than the latter), then find the first whitespace character with \s. Putting these together, you have

^[^\s]*\s

You may want to group the non-whitespace and whitespace parts, so you can do the replacement you're talking about:

^([^\s]*)(\s)

Then the replacement pattern is just \1/

Answer 2

You can use this regex.

^([^\s]*)\s