How to instantiate a type dynamically using reflection?

Question

I need to instatiate a C# type dynamically, using reflection. Here is my scenario: I am writing a base class, which will need to instantiate a certain object as a part of its in

Answer 1

You might want to use generics instead:

public abstract class MyBaseClass<T> where T : new()
{
    protected MyBaseClass()
    {
        T myObj = new T();
         // Instantiate object of type passed in 
         /* This is the part I'm trying to figure out */
    }
}

public class MyDerivedClass : MyBaseClass<Whatever>
{
    public MyDerivedClass() 
    {
    }
}

The where T : new() is required to support the new T() construct.

Answer 2

Try Activator.CreateInstance(Type)

http://msdn.microsoft.com/en-us/library/wccyzw83.aspx

Answer 3

You're looking for Activator.CreateInstance

object instance = Activator.CreateInstance(myType);

There are are various overloads of this method that can take constructor arguments or other information to find the type (such as names in string form)

• http://msdn.microsoft.com/en-us/library/system.activator.createinstance.aspx