variable as index in an associative array - Javascript

Question

I\'m trying to create an associative array, create an empty array, and then add a (indexName -> value) pair:

var arrayName = new Array;

arrayName[\         


        

Answer 1

At first I don't think you need a real array object to do what you need, you can use a plain object.

You can simply use the bracket notation to access a property, using the value of a variable:

var obj = {};
var nume = var1 + var2;
obj[nume] = value;

Array's are simply objects, the concept of an "associative array" can be achieved by using a simple object, objects are collections of properties that contain values.

True arrays are useful when you need to store numeric indexes, they automatically update their length property when you assign an index or you push a value to it.

Answer 2

Indeed, there was no need for an array object, a simple object did the job; further more an array introduced the need to use quotes inside the square brackets obj["var1 + var2"] to access the object property's value and not the value associated with an index (i think); the quotes transformed "var1 + var2" into a string. Using a simple object eliminated the need for quotes, so I can use obj[var1 + var2], wich worked :)

Thanks everyone !

Answer 3

Are you looking for variableName = 'bla'+'foo'; arrayRef[variableName] = 'something'; ?

And even so, you should use an object literal instead. x = {}; x[variablename] = 'blah';

Answer 4

You would use objects to do that:

var hash = {}
hash["foo"] = "foo";
hash.bar    = "bar";
// This is the dynamic approach: Your key is a string:
baz         = "baz"
hash[baz]   = "hello";

To iterate, just use a for loop or $.each() in jQuery.

Answer 5

use arrayName[var1+var2]

Note that arrayName.var is the same as arrayName["var"] -- it's just syntactic sugar. The second form is mostly used when dealing with the kind of problems that you are facing - dynamic object keys, and keys that are not alphanumeric (think of arrayName[".eval()"]; this is a perfectly legal object key that has nothing to do with the javascript eval() function)

Answer 6

I did something like like following;

let parentArray = [];
let childArray = [1, 2, 3];
childArray.name = 'my-array-1';
parentArray.push(childArray);

To access that by name in ES6;

parentArray.filter(x => x.name == 'my-array-1');