Git - list all authors of a folder of files?

Question

How can I list the author names of a particular folder that\'s versioned by git?

I see that I can git blame a file and list the author of each line, but I c

Answer 1

Actually, there is a native Git command for that, git shortlog:

git shortlog -n -s -- myfolder

will give a list of contributors that created commits that touched myfolder. By omitting option -s, the summary even lists the commit message summaries per author. Option -n sorts the authors by number of commits (from most to least) instead of alphabetical.

And just in case you have not encountered a loose -- in a git command yet: it is a separator option to mark that what follows cannot be a <revspec> (range of commits), but only a <pathspec> (file and folder names). That means: if you would omit the -- and by accident had a branch or tag named myfolder, the command git shortlog -n -s myfolder would not filter for the directory myfolder, but instead filter for history of branch or tag "myfolder". This separator is therefore useful (and necessary) in a number of git commands, like log or checkout, whenever you want to be clear whether what you specify is either a revision (commmit, branch, tag) or a path (folder or file name). An of course, this site already has a question on this.

Answer 2

If you want only the list of authors of a repository:

git ls-files | xargs -n1 git blame --line-porcelain | sed -n 's/^author //p' | sort -d | uniq

If you want to do it for a file order by the number of lines of code contributions it is simple:

git blame --line-porcelain "_MY_FILE_" | sed -n 's/author //p' | sort | uniq -c | sort -rn

If you want to do it for the whole repository also ordered by code contributions:

git ls-files | xargs -n1 git blame --line-porcelain | sed -n 's/^author //p' | sort -f | uniq -ic | sort -nr

Answer 3

Based on The shortest possible output from git log containing author and date

do this

git log --pretty=format:"%an%x09" myfolder | sort | uniq