Why double.TryParse(“0.0000”, out doubleValue) returns false ?

Question

I am trying to parse string \"0.0000\" with double.TryParse() but I have no idea why would it return false in this particular example. When I pass integer-like stri

Answer 1

The most stupid thing about this is that it only accept "," as decimal separator in my culture, but the result is with a ".". Someone, somewhere, wasn't very lucky thinking that day... So I'll try this:

if ((double.TryParse(sVat, out vat)) == false)
    if (double.TryParse(sVat.Replace(",", "."), out vat) == false)
      double.TryParse(sVat.Replace(".", ","), out vat);

Answer 2

To change the culture to something that has "." as decimal separator use:

Thread.CurrentThread.CurrentCulture = new CultureInfo("en-GB");

Answer 3

TryParse uses the current culture by default. And if your current culture uses a decimal seperator different from ., it can't parse 0.0000 as you intend. So you need to pass in CultureInfo.InvariantCulture.

var numberStyle = NumberStyles.AllowLeadingWhite |
                 NumberStyles.AllowTrailingWhite |
                 NumberStyles.AllowLeadingSign |
                 NumberStyles.AllowDecimalPoint |
                 NumberStyles.AllowThousands |
                 NumberStyles.AllowExponent;//Choose what you need
double.TryParse( "0.0000", numberStyle, CultureInfo.InvariantCulture, out myVar)