char str[] = \"beautiful earth\";
memset(str, \'*\', 6);
printf(\"%s\", str);
Output:
******ful earth
Like the above use of memset, can we initial
The third argument of memset is byte size. So you should set total byte size of arr[15]
memset(arr, 1, sizeof(arr));
However probably, you should want to set value 1 to whole elements in arr. Then you've better to set in the loop.
for (i = 0; i < sizeof(arr)/sizeof(arr[0]); i++) {
arr[i] = 1;
}
Because memset()
set 1 in each bytes. So it's not your expected.
Short answer, NO.
Long answer, memset
sets bytes and works for characters because they are single bytes, but integers are not.
No, you cannot use memset()
like this. The manpage says (emphasis mine):
The
memset()
function fills the firstn
bytes of the memory area pointed to bys
with the constant bytec
.
Since an int
is usually 4 bytes, this won't cut it.
If you (incorrectly!!) try to do this:
int arr[15];
memset(arr, 1, 6*sizeof(int)); //wrong!
then the first 6 int
s in the array will actually be set to 0x01010101 = 16843009.
The only time it's ever really acceptable to write over a "blob" of data with non-byte datatype(s), is memset(thing, 0, sizeof(thing));
to "zero-out" the whole struture/array. This works because NULL, 0x00000000, 0.0, are all completely zeros.
The solution is to use a for
loop and set it yourself:
int arr[15];
int i;
for (i=0; i<6; ++i) // Set the first 6 elements in the array
arr[i] = 1; // to the value 1.
Ideally you can not use memset to set your arrary to all 1.
Because memset works on byte and set every byte to 1.
memset(hash, 1, cnt);
So once read, the value it will show 16843009 = 0x01010101 = 1000000010000000100000001
Not 0x00000001
But if your requiremnt is only for bool or binary value then we can set using C99 standard for C library
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <stdbool.h> //Use C99 standard for C language which supports bool variables
int main()
{
int i, cnt = 5;
bool *hash = NULL;
hash = malloc(cnt);
memset(hash, 1, cnt);
printf("Hello, World!\n");
for(i=0; i<cnt; i++)
printf("%d ", hash[i]);
return 0;
}
Output:
Hello, World!
1 1 1 1 1