How to get the current running module path/name

Question

I\'ve searched and this seems to be a simple question without a simple answer.

I have the file a/b/c.py which would be called with python -m a.b.c

Answer 1

Why does nobody mentioned the .__module__?

When doing a self.__module__ you will get the module path. You can also do this outside of the class:

Class A:
   self.__module__  # gets module.filename

def get_module():
    A.__module__ # also gets module.filename