C++11 auto declaration with and without pointer declarator

Question

What\'s the difference between the types of bar1 and bar2?

int foo = 10;
auto bar1 = &foo;
auto *bar2 = &foo;

Answer 1

Using auto * "documents intention". And auto *p = expr; can be deduced correctly only if expr returns pointer. Example:

int f();

auto q = f(); // OK

auto *p = f(); // error: unable to deduce 'auto*' from 'f()'