Path to a file without basename

Question

How can I get the path of a file without the file basename ?

Something like /a/path/to/my/file.txt --> /a/path/to/my/

Tried with .split

Answer 1

You can import os

>>> filepath
'/a/path/to/my/file.txt'
>>> os.path.dirname(filepath)
'/a/path/to/my'
>>>