I read through various threads like this one for example.
But it really escapes me how to accomplish the following:
I have 4 functions, and want them happen one
It's a great chance to start using jQuery Deferred.
Apart from the callbacks-based solution the code is readable, flexible and highly maintainable
http://jsfiddle.net/zerkms/zJhph/
function firstFunction(){
var d = $.Deferred();
// some very time consuming asynchronous code...
setTimeout(function() {
console.log('1');
d.resolve();
}, 1000);
return d.promise();
}
function thirdFunction(){
var d = $.Deferred();
// definitely dont wanna do this until secondFunction is finished
setTimeout(function() {
console.log('3');
d.resolve();
}, 1000);
return d.promise();
}
function secondFunction(){
var d = $.Deferred();
setTimeout(function() {
console.log('2');
d.resolve();
}, 1000);
return d.promise();
}
function fourthFunction(){
var d = $.Deferred();
// last function, not executed until the other 3 are done.
setTimeout(function() {
console.log('4');
d.resolve();
}, 1000);
return d.promise();
}
firstFunction().pipe(secondFunction).pipe(thirdFunction).pipe(fourthFunction);
PS: as an example of asynchronous code I've used setTimeout
. The main thing is that in the end of the asynchronous part you need to call d.resolve()
to continue chaining methods.
Further reading: http://joseoncode.com/2011/09/26/a-walkthrough-jquery-deferred-and-promise/