Pythonic way to check if: all elements evaluate to False -OR- all elements evaluate to True

Question

I want the results of the function to be:

• All values evaluate to False (None, 0, empty string) -> True
• All values evaluate to True -> True
• Every

Answer 1

Piggybacking on Ignacio Vasquez-Abram's method, but will stop after first mismatch:

def unanimous(s):
  it1, it2 = itertools.tee(iter(s))
  it1.next()
  return not any(bool(a)^bool(b) for a,b in itertools.izip(it1,it2))

While using not reduce(operators.xor, s) would be simpler, it does no short-circuiting.