Get “real” class of generic type

Question

How can I get the \"real\" class of a generic type?

For Example:

public class MyClass {
    public void method(){
        //something

        S         


        

Answer 1

You can't. The information is stripped from the code at compile time, a process that is known as type erasure. For more, please look here: Type Erasure

edit: sorry my bad, the information is not loaded at run time.