Detecting a timeout for a block of code in PHP

Question

Is there a way you can abort a block of code if it\'s taking too long in PHP? Perhaps something like:

//Set the max time to 2 seconds
$time = new TimeOut(2);
$ti         


        

Answer 1

You can use declare function if the execution time exceeds the limits. http://www.php.net/manual/en/control-structures.declare.php

Here a code example of how to use

define("MAX_EXECUTION_TIME", 2); # seconds

$timeline = time() + MAX_EXECUTION_TIME;

function check_timeout()
{
    if( time() < $GLOBALS['timeline'] ) return;
    # timeout reached:
    print "Timeout!".PHP_EOL;
    exit;
}

register_tick_function("check_timeout");
$data = "";

declare( ticks=1 ){
    # here the process that might require long execution time
    sleep(5); // Comment this line to see this data text
    $data = "Long process result".PHP_EOL;
}

# Ok, process completed, output the result:
print $data;

With this code you will see the timeout message. If you want to get the Long process result inside the declare block you can just remove the sleep(5) line or increase the Max Execution Time declared at the start of the script