How to manually return a Result<(), Box>?

Question

I want to return an error from a function in case a condition is true:

use std::error::Error;

pub fn run() -> Result<(), Box> {
    //         


        

Answer 1

Error is a trait and you want to return a trait object (note the dyn keyword), so you need to implement this trait:

use std::error::Error;
use std::fmt;

#[derive(Debug)]
struct MyError(String);

impl fmt::Display for MyError {
    fn fmt(&self, f: &mut fmt::Formatter) -> fmt::Result {
        write!(f, "There is an error: {}", self.0)
    }
}

impl Error for MyError {}

pub fn run() -> Result<(), Box> {
    let condition = true;

    if condition {
        return Err(Box::new(MyError("Oops".into())));
    }

    Ok(())
}

fn main() {
    if let Err(e) = run() {
        println!("{}", e); // "There is an error: Oops"
    }
}

• Create your own error type,
• Implement Debug, Display, then Error for it,
• If there is an error, return the Err variant of Result.

I advise you to use failure that remove all the error boilerplate:

#[derive(Fail, Debug)]
#[fail(display = "There is an error: {}.", _0)]
struct MyError(String);

--

Note that if you expect an Error, you can return whatever type you want, given that it implements Error. This includes the error types in std.