SELECT N rows before and after the row matching the condition?

Question

The behaviour I want to replicate is like grep with -A and -B flags . eg grep -A 2 -B 2 \"hello\" myfile.txt will give me all the lines wh

Answer 1

Adding an answer using date instead of an id. The use-case here is an on-call rotation table with one record pr week. Due to edits the id might be out of order for the purpose intended. Any use-case having several records pr week, pr date or other will of course have to be mended.

+----------+--------------+------+-----+---------+----------------+
| Field    | Type         | Null | Key | Default | Extra          |
+----------+--------------+------+-----+---------+----------------+
| id       | int(11)      | NO   | PRI | NULL    | auto_increment |
| startdate| datetime     | NO   |     | NULL    |                |
| person   | int(11)      | YES  | MUL | NULL    |                |
+----------+--------------+------+-----+---------+----------------+

The query:

SELECT child.*
FROM rota-table as child,
 (SELECT startdate
    FROM rota-table
    WHERE YEARWEEK(startdate, 3) = YEARWEEK(now(), 3) ) as parent
WHERE
    YEARWEEK(child.startdate, 3) >= YEARWEEK(NOW() - INTERVAL 25 WEEK, 3)
    AND YEARWEEK(child.startdate, 3) <= YEARWEEK(NOW() + INTERVAL 25 WEEK, 3)