Pointer/address type casting

Question

I have the following variables:

char *p;
int l=65;

Why do the following casts fail?

(int *)p=&l;

and:

Answer 1

The problem is that when you're performing the casts (aside from whether or not the kind of casting you're doing is a good idea or not) is that the cast expression results in an rvalue.

rvalues cannot be assigned to or have their addreses taken.