Here is an example from Hadley\'s advanced R book:
sample_df <- data.frame(a = 1:5, b = 5:1, c = c(5, 3, 1, 4, 1))
subset2 <- function(x, condition) {
c
When subset2()
is called from within subscramble()
,
condition_call
's value is the symbol condition
(rather than the
call a >= 4
that results when it is called directly). subset()
's
call to eval()
searches for condition
first in envir=x
(the
data.frame sample_df
). Not finding it there, it next searches in enclos=parent.frame()
where it does find an object named
condition
.
That object is a promise object, whose expression slot is
a >= 4
and whose evaluation environment is .GlobalEnv
. Unless an
object named a
is found in .GlobalEnv
or further up the search
path, evaluation of the promise then fails with the observed message
that: Error in eval(expr, envir, enclos) : object 'a' not found
.
A nice way to discover what's going wrong here is to insert a
browser()
call right before the line at which subset2()
fails. That way, we can call it both directly and indirectly (from
within another function), and examine why it succeeds in the first case and
fails in the second.
subset2 <- function(x, condition) {
condition_call <- substitute(condition)
browser()
r <- eval(condition_call, x, parent.frame()) ## <- Point of failure
x[r, ]
}
When a user calls subset2()
directly,
condition_call <- substitute(condition)
assigns to condition_call
a "call" object
containing the unevaluated call a >= 4
. This call is passed in to
eval(expr, envir, enclos)
, which needs as its first argument a
symbol that evaluates to an object of class call
, name
, or
expression
. So far so good.
subset2(sample_df, a >= 4)
## Called from: subset2(sample_df, a >= 4)
Browse[1]> is(condition_call)
## [1] "call" "language"
Browse[1]> condition_call
## a >= 4
eval()
now sets to work, searching for the values of any symbols
contained in expr=condition_call
first in envir=x
and then (if
needed) in enclos=parent.frame()
and its enclosing environments. In
this case, it finds the symbol a
in envir=x
(and the symbol >=
in package:base
) and successfully completes the evaluation.
Browse[1]> ls(x)
## [1] "a" "b" "c"
Browse[1]> get("a", x)
## [1] 1 2 3 4 5
Browse[1]> eval(condition_call, x, parent.frame())
## [1] FALSE FALSE FALSE TRUE TRUE
Within the body of subscramble()
, subset2()
is called like this:
subset2(x, condition)
. Fleshed out, that call is really equivalent
to subset2(x=x, condition=condition)
. Because its supplied
argument (i.e. the value passed to the formal argument named
condition
) is the expression condition
,
condition_call <- substitute(condition)
assigns to condition_call
the symbol object condition
. (Understanding that point is pretty key to understanding exactly how the nested call fails.)
Since eval()
is happy to have a symbol (aka "name") as its first
argument, once again so far so good.
subscramble(sample_df, a >= 4)
## Called from: subset2(x, condition)
Browse[1]> is(condition_call)
## [1] "name" "language" "refObject"
Browse[1]> condition_call
## condition
Now eval()
goes to work searching for the unresolved symbol
condition
. No column in envir=x
(the data.frame sample_df
)
matches, so it moves on to enclos=parent.frame()
For fairly
complicated reasons, that environment turns out to be the evaluation
frame of the call to subscramble()
. There, it does find
an object named condition
.
Browse[1]> ls(x)
## [1] "a" "b" "c"
Browse[1]> ls(parent.frame()) ## Aha! Here's an object named "condition"
## [1] "condition" "x"
As an important aside, it turns out there are several objects named condition
on the call stack above the environment from which browser()
was called.
Browse[1]> sys.calls()
# [[1]]
# subscramble(sample_df, a >= 4)
#
# [[2]]
# scramble(subset2(x, condition))
#
# [[3]]
# subset2(x, condition)
#
Browse[1]> sys.frames()
# [[1]]
# ## <- Envt in which `condition` is evaluated
#
# [[2]]
#
#
# [[3]]
# ## <- Current environment
## Orient ourselves a bit more
Browse[1]> environment()
#
Browse[1]> parent.frame()
#
## Both environments contain objects named 'condition'
Browse[1]> ls(environment())
# [1] "condition" "condition_call" "x"
Browse[1]> ls(parent.frame())
# [1] "condition" "x"
To inspect the condition
object found by eval()
(the one in parent.frame()
, which turns out to be the evaluation frame of subscramble()
) takes some special care. I used recover()
and pryr::promise_info()
as shown below.
That inspection reveals that condition
is a promise whose expression slot is a >= 4
and whose
environment is .GlobalEnv
. Our search for a
has by this point moved well
past sample_df
(where a value of a
was to be found), so evaluation of the
expression slot fails (unless an object named a
is found in .GlobalEnv
or
somewhere else farther up the search path).
Browse[1]> library(pryr) ## For is_promise() and promise_info()
Browse[1]> recover()
#
# Enter a frame number, or 0 to exit
#
# 1: subscramble(sample_df, a >= 4)
# 2: #2: scramble(subset2(x, condition))
# 3: #1: subset2(x, condition)
#
Selection: 1
# Called from: top level
Browse[3]> is_promise(condition)
# [1] TRUE
Browse[3]> promise_info(condition)
# $code
# a >= 4
#
# $env
#
#
# $evaled
# [1] FALSE
#
# $value
# NULL
#
Browse[3]> get("a", .GlobalEnv)
# Error in get("a", .GlobalEnv) : object 'a' not found
For one more piece of evidence that the promise object condition
is being found
in enclos=parent.frame()
, one can point enclos
somewhere else farther up
the search path, so that parent.frame()
is skipped during condition_call
's evaluation. When one does
that, subscramble()
again fails, but this time with a message that
condition
itself was not found.
## Compare
Browse[1]> eval(condition_call, x, parent.frame())
# Error in eval(expr, envir, enclos) (from #4) : object 'a' not found
Browse[1]> eval(condition_call, x, .GlobalEnv)
# Error in eval(expr, envir, enclos) (from #4) : object 'condition' not found