Combining two uint8_t as uint16_t

Question

I have the following data

uint8_t d1=0x01; 
uint8_t d2=0x02; 

I want to combine them as uint16_t as

uint16_t wd =         


        

Answer 1

You can use bitwise operators:

uint16_t wd = ((uint16_t)d2 << 8) | d1;

Because:

 (0x0002 << 8) | 0x01 = 0x0200 | 0x0001 = 0x0201