Scala inherit parameterized constructor

Question

I have an abstract base class with several optional parameters:

abstract case class Hypothesis(
    requirement: Boolean = false,
    onlyDays:   Seq[Int] = Nil,         


        

Answer 1

You can just use a dummy name in the inherited class:

case class SomeHypothesis(anotherArg: SomeType, rq: Boolean = false, odays: Seq[Int] = Nil)
extends Hypothesis(rq, odays)

but you do have to repeat the default values. There is no need to override a val.

EDIT:

Note that your abstract class should not be a case class. Extending case classes is now deprecated. You should use an extractor for you abstract class instead:

abstract class SomeHypothesis(val request: Boolean)

object SomeHypothesis {
  def unapply(o: Any): Option[Boolean] = o match {
    case sh: SomeHypothesis => Some(sh.request)
    case _ => None
  }
}