Django FileField (or ImageField) open() method returns None for valid file?

Question

let me put it like this:

model.py:

class Task(models.Model):
    ...
    seq_file = models.FileField(upload_to=\'files/\', blank=True, null=True)
    ...         


        

Answer 1

because open method of models.FileField doesn't return anything

you can just use:

task.seq_file.read()

and you don't need calculate path of file for checking if file exist. you can use task.seq_file.path:

if not os.path.isfile(task.seq_file.path):
    ....