How to safely get the file extension from a URL?

Question

Consider the following URLs

http://m3u.com/tunein.m3u
http://asxsomeurl.com/listen.asx:8024
http://www.plssomeotherurl.com/station.pls?id=111
http://22.198.133.16:802         


        

Answer 1

you can try the rfc6266 module like：

import requests
import rfc6266

req = requests.head(downloadLink)
headersContent = req.headers['Content-Disposition']
rfcFilename = rfc6266.parse_headers(headersContent, relaxed=True).filename_unsafe
filename = requests.utils.unquote(rfcFilename)