Zsh includes the ability to display the return code/exit code of the previous command in the prompt by using the %?
escape sequence.
However I would like to
Add this in the position in PS1
where you want the exit code to appear:
%(?..[%?] )
It's a conditional expression. The part between the two dots (nothing in this case) is output if the expression before the first dot is true. The part after the second dot is output if it's false.
For example:
PS1='%n%m %~ %(?..[%?] )%# '