Print rest of the fields in awk

Question

Suppose we have this data file.

john 32 maketing executive
jack 41 chief technical officer
jim  27 developer
dela 33 assistant risk management officer
         


        

Answer 1

Approach using awk that would not require gawk or any state mutations:

awk '{print $1 " " substr($0, index($0, $3));}' datafile

UPD

solution that is a bit longer, but will stand up the case when $1 or $2 contains $3:

awk '{print $1 " " substr($0, length($1 $2) + 1);}' data

Or even more robust if you have custom field separator:

awk '{print $1 " " substr($0, length($1 FS $2 FS) + 1);}' data