Print rest of the fields in awk

Question

Suppose we have this data file.

john 32 maketing executive
jack 41 chief technical officer
jim  27 developer
dela 33 assistant risk management officer
         


        

Answer 1

You can use simple awk like this:

awk '{$2=""}1' file

However this will have an extra OFS in your output that can be avoided by this awk

awk '{sub($2 OFS, "")}1' file

OR else by using this tr and cut combo:

On Linux:

tr -s ' ' < file | cut -d ' ' -f1,f3-

On OSX:

tr -s ' ' < file | cut -d ' ' -f1 -f3-