Observable which does not pass anything in onNext()

Question

I would need an Observable, for example to provide a system clock, which does not need to pass anything in onNext(). I couldn\'t find a signature that would allow me to do that.

Answer 1

I don't know this will helps you or not.
The code written in RxSwift.

// Create an observable and emit somethings
let myObservable = Observable.create{ observer in
    observer.on(.next(Void()))
    return Disposables.create()
}

// Observer subscribe changes
myObservable.subscribe(onNext: {
    _ in
    print("Hello")
}).disposed(by: disposeBag)

Or use the Variable object

// Create a Variable object that contanins nothing
var myValueWatcher:Variable = Variable(Void())

// Observer subscribe changes
myValueWatcher.asObservable().skip(1).subscribe(onNext: {
    _ in
    print("Changes!")
}).disposed(by: disposeBag)


// The emit code
myValueWatcher.value = Void()