I need to square a 2D numpy array (elementwise) and I have tried the following code:
import numpy as np
a = np.arange(4).reshape(2, 2)
print a^2, \'\\n\'
print a
The fastest way is to do a*a
or a**2
or np.square(a)
whereas np.power(a, 2)
showed to be considerably slower.
np.power()
allows you to use different exponents for each element if instead of 2
you pass another array of exponents. From the comments of @GarethRees I just learned that this function will give you different results than a**2
or a*a
, which become important in cases where you have small tolerances.
I've timed some examples using NumPy 1.9.0 MKL 64 bit, and the results are shown below:
In [29]: a = np.random.random((1000, 1000))
In [30]: timeit a*a
100 loops, best of 3: 2.78 ms per loop
In [31]: timeit a**2
100 loops, best of 3: 2.77 ms per loop
In [32]: timeit np.power(a, 2)
10 loops, best of 3: 71.3 ms per loop