Appending an id to a list if not already present in a string

Question

I am trying to check if id is in a list and append the id only if its not in the list using the below code..however I see that the id is getting appended even though id is alre

Answer 1

Your list just contains a string. Convert it to integer IDs:

L = ['350882 348521 350166\r\n']

ids = [int(i) for i in L[0].strip().split()]
print(ids)
id = 348521
if id not in ids:
    ids.append(id)
print(ids)
id = 348522
if id not in ids:
    ids.append(id)
print(ids)
# Turn it back into your odd format
L = [' '.join(str(id) for id in ids) + '\r\n']
print(L)

Output:

[350882, 348521, 350166]
[350882, 348521, 350166]
[350882, 348521, 350166, 348522]
['350882 348521 350166 348522\r\n']