How can we truncate float64 type to a particular precision?

Question

package main

import (
    \"fmt\"
    \"strconv\"
    )

func main() {
    k := 10/3.0
    i := fmt.Sprintf(\"%.2f\", k)
    f,_ := strconv.ParseFloat(i, 2)
    fmt.Pri         


        

Answer 1

Functions without checking for large floats

// Rounds like 12.3416 -> 12.35
func RoundUp(val float64, precision int) float64 {
    return math.Ceil(val*(math.Pow10(precision))) / math.Pow10(precision)
}

// Rounds like 12.3496 -> 12.34
func RoundDown(val float64, precision int) float64 {
    return math.Floor(val*(math.Pow10(precision))) / math.Pow10(precision)
}

// Rounds to nearest like 12.3456 -> 12.35
func Round(val float64, precision int) float64 {
    return math.Round(val*(math.Pow10(precision))) / math.Pow10(precision)
}