Display foreign key columns as link to detail object in Django admin

Question

As explained in link-in-django-admin-to-foreign-key-object, one can display a ForeignKey field as a link to the admin detail page.

To summarize,

class Fo         


        

Answer 1

A good start would be looking at the source of BaseModelAdmin and ModelAdmin. Try to find out how the ModelAdmin generates the default links. Extend ModelAdmin, add a method to generate links to arbitrary foreign keys and look at how ChangeList generates the change list.

I would also suggest you use format_html to render the links, which makes link_to_bar.allow_tags = True unnecessary:

from django.utils.html import format_html

class FooAdmin(ModelAdmin):
    list_display = ('link_to_bar', )
    def link_to_bar(self, obj):
        link = urlresolvers.reverse('admin:app_bar_change', args=[obj.bar_id])
        return format_html('{}', link, obj.bar) if obj.bar else None