def x_smallest(items, x):
result = sorted(items[:x])
for i in items[x:]:
if i < result[-1]:
result[-1] = i
j = x - 1
while j > 0 and result[j] < result[j-1]:
result[j-1], result[j] = result[j], result[j-1]
j -= 1
return result
Worst case is O(x*n), but will typically be closer to O(n).