C++0x rvalue references and temporaries

Question

(I asked a variation of this question on comp.std.c++ but didn\'t get an answer.)

Why does the call to f(arg) in this code call the const ref overload of

Answer 1

I don't know if that has changed in the latest versions of the standard, but it used to say something like "if in doubt, don't use the rvalue reference". Probably for compatibility reasons.

If you want the move semantics, use f(std::move(arg)), that works with both compilers.