Why doesn't Python's nonlocal keyword like the global scope?

Question

In Python 3.3.1, this works:

i = 76

def A():
    global i
    i += 10

print(i) # 76
A()
print(i) # 86

This also works:

def en         


        

Answer 1

The search order for names is LEGB, i.e Local, Enclosing, Global, Builtin. So the global scope is not an enclosing scope.

EDIT

From the docs:

The nonlocal statement causes the listed identifiers to refer to previously bound variables in the nearest enclosing scope. This is important because the default behavior for binding is to search the local namespace first. The statement allows encapsulated code to rebind variables outside of the local scope besides the global (module) scope.