Is it possible to make a squiggly line?

Question

If I wanted to make a horizontal line, I would do this:

Answer 1

﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏

& #65103 ; (wavy low line)

I hope this is not too much off topic - here is how to use those squiggly lines to underline some text (should be a common use case.)

method 1 (snatched from Wulf answering a related question)

    
        foobar
    

(not really a squiggly line but a collection of dots, but looks OK and is beautifully simple.)

method 2 (inspired by DanieldD)

using & #65103 ; (wavy low line) unicode character and absolute / relative positioning to put that character underneath some text. Here is a fiddle

here is "the meat" of the code for the positioning

function performUnderWavyLowLineazation(contentElt){
    var wavyFontSize = 40;
    var width = contentElt.width();
    contentElt.addClass("underWavyLowLined");
    replaceSpaceByNonBreakingSpace(contentElt);
    var sp = "";
    var wrapper = contentElt.wrap(sp).parent();
    wrapper.addClass("wavyParent");
    var underlining = jQuery(sp, {"class" : "wavyLowLine"}).prependTo(wrapper);
    var ghost;
    var invisibleGhostThatTakesUpTheSpaceThatUnderWavyLowLinedElementShouldTakeButDoesntDueToBeingAbsolute
        = ghost = jQuery(sp, {"class": "invisibleUnderWavyLowLined"}).appendTo(wrapper);
    ghost.html(contentElt.html());
    ghost.find("*").removeAttr("id");
    replaceSpaceByNonBreakingSpace(ghost);
    var numWavyChars = Math.floor(0.1 + width/wavyFontSize);
    innerUnderLine = jQuery(sp, {"class": "innerWaveLine"}).appendTo(underlining);
    innerUnderLine.html("﹏".repeat(numWavyChars));
    var lineLength = wavyFontSize * numWavyChars;
    var defect = width - lineLength;
    innerUnderLine.css("left", defect/2);
    var wavyGroup = jQuery(sp, {"class" : "wavyGroup"}).prependTo(wrapper);
    underlining.appendTo(wavyGroup);
    contentElt.appendTo(wavyGroup);
}