Python format size application (converting B to KB, MB, GB, TB)

Question

I am trying to write an application to convert bytes to kb to mb to gb to tb. Here\'s what I have so far:

def size_format(b):
    if b < 1000:
              r         


        

Answer 1

def humanbytes(B):
   'Return the given bytes as a human friendly KB, MB, GB, or TB string'
   B = float(B)
   KB = float(1024)
   MB = float(KB ** 2) # 1,048,576
   GB = float(KB ** 3) # 1,073,741,824
   TB = float(KB ** 4) # 1,099,511,627,776

   if B < KB:
      return '{0} {1}'.format(B,'Bytes' if 0 == B > 1 else 'Byte')
   elif KB <= B < MB:
      return '{0:.2f} KB'.format(B/KB)
   elif MB <= B < GB:
      return '{0:.2f} MB'.format(B/MB)
   elif GB <= B < TB:
      return '{0:.2f} GB'.format(B/GB)
   elif TB <= B:
      return '{0:.2f} TB'.format(B/TB)

tests = [1, 1024, 500000, 1048576, 50000000, 1073741824, 5000000000, 1099511627776, 5000000000000]

for t in tests: print '{0} == {1}'.format(t,humanbytes(t))

Output:

1 == 1.0 Byte
1024 == 1.00 KB
500000 == 488.28 KB
1048576 == 1.00 MB
50000000 == 47.68 MB
1073741824 == 1.00 GB
5000000000 == 4.66 GB
1099511627776 == 1.00 TB
5000000000000 == 4.55 TB

and for future me here it is in Perl too:

sub humanbytes {
   my $B = shift;
   my $KB = 1024;
   my $MB = $KB ** 2; # 1,048,576
   my $GB = $KB ** 3; # 1,073,741,824
   my $TB = $KB ** 4; # 1,099,511,627,776

   if ($B < $KB) {
      return "$B " . (($B == 0 || $B > 1) ? 'Bytes' : 'Byte');
   } elsif ($B >= $KB && $B < $MB) {
      return sprintf('%0.02f',$B/$KB) . ' KB';
   } elsif ($B >= $MB && $B < $GB) {
      return sprintf('%0.02f',$B/$MB) . ' MB';
   } elsif ($B >= $GB && $B < $TB) {
      return sprintf('%0.02f',$B/$GB) . ' GB';
   } elsif ($B >= $TB) {
      return sprintf('%0.02f',$B/$TB) . ' TB';
   }
}