Pass parameter to an awk script file

Question

If I want to pass a parameter to an awk script file, how can I do that ?

#!/usr/bin/awk -f

{print $1}

Here I want to print the first argument

Answer 1

In awk $1 references the first field in a record not the first argument like it does in bash. You need to use ARGV for this, check out here for the offical word.

Script:

#!/bin/awk -f

BEGIN{
    print "AWK Script"
    print ARGV[1]
}

Demo:

$ ./script.awk "Passed in using ARGV"
AWK Script
Passed in using ARGV