How to omit specific properties from an object in JavaScript

Question

Is there a clean way to return a new object that omits certain properties that the original object contains without having to use something like lodash?

Answer 1

One solution, I'm sure many others exist.

const testObj = {
    prop1: 'value1',
    prop2: 'value2',
    prop3: 'value3'
};

const removeProps = (...propsToFilter) => obj => {
   return Object.keys(obj)
   .filter(key => !propsToFilter.includes(key))
   .reduce((newObj, key) => {
       newObj[key] = obj[key];
       return newObj;
   }, {});
};


console.log(removeProps('prop3')(testObj));
console.log(removeProps('prop1', 'prop2')(testObj));

Edit: I always forget about delete...

const testObj = {
    prop1: 'value1',
    prop2: 'value2',
    prop3: 'value3'
};

const removeProps = (...propsToFilter) => obj => {
   const newObj = Object.assign({}, obj);
   propsToFilter.forEach(key => delete newObj[key]);
   return newObj;
};


console.log(removeProps('prop3')(testObj));
console.log(removeProps('prop1', 'prop2')(testObj));