Shell script to open a URL

Question

How do I write a simple shell script (say script.sh), so that I can pass a URL as an argument while executing?

I want a browser to start with the page opened on that URL

Answer 1

If you want a cross-OS solution and are comfortable using Python (3):

Try this:

import webbrowser

webbrowser.open('https://yoururl.com')

Or in a terminal/cmd:

python -m webbrowser -t "https://yoururl.com"