Go golang, syntax error: unexpected ++, expecting :

后端 未结 4 861
醉梦人生
醉梦人生 2021-02-01 13:10
  func test(args ...string) {
    var msg map[string] interface{}

    i := 0
    msg[\"product\"] = args[i++]
    msg[\"key\"] = args[i++]
    msg[\"signature\"] = args         


        
4条回答
  •  故里飘歌
    2021-02-01 14:03

    Go Frequently Asked Questions (FAQ)

    Why are ++ and -- statements and not expressions? And why postfix, not prefix?

    Without pointer arithmetic, the convenience value of pre- and postfix increment operators drops. By removing them from the expression hierarchy altogether, expression syntax is simplified and the messy issues around order of evaluation of ++ and -- (consider f(i++) and p[i] = q[++i]) are eliminated as well. The simplification is significant. As for postfix vs. prefix, either would work fine but the postfix version is more traditional; insistence on prefix arose with the STL, a library for a language whose name contains, ironically, a postfix increment.

    The Go Programming Language Specification

    IncDec statements

    The "++" and "--" statements increment or decrement their operands by the untyped constant 1. As with an assignment, the operand must be addressable or a map index expression.

    IncDecStmt = Expression ( "++" | "--" ) .
    

    The following assignment statements are semantically equivalent:

    IncDec statement    Assignment
    x++                 x += 1
    x--                 x -= 1
    

    Write,

    func test(args ...string) {
        var msg map[string]interface{}
        i := 0
        msg["product"] = args[i]
        i++
        msg["key"] = args[i]
        i++
        msg["signature"] = args[i]
        i++
        msg["string_to_sign"] = args[i]
    }
    

    Which, in your particular case, simplifies to,

    func test(args ...string) {
        var msg map[string]interface{}
        msg["product"] = args[0]
        msg["key"] = args[1]
        msg["signature"] = args[2]
        msg["string_to_sign"] = args[3]
    }
    

提交回复
热议问题