How to represent a fix number of repeats in regular expression?

Question

I am wondering if there is a better to represent a fix amount of repeats in a regular expression. For example, if I just want to match exactly 14 letters/digits, I am using

Answer 1

The finite repetition syntax uses {m,n} in place of star/plus/question mark.

From java.util.regex.Pattern:

X{n}      X, exactly n times
X{n,}     X, at least n times
X{n,m}    X, at least n but not more than m times

All repetition metacharacter have the same precedence, so just like you may need grouping for *, +, and ?, you may also for {n,m}.

• ha* matches e.g. "haaaaaaaa"
• ha{3} matches only "haaa"
• (ha)* matches e.g. "hahahahaha"
• (ha){3} matches only "hahaha"

Also, just like *, +, and ?, you can add the ? and + reluctant and possessive repetition modifiers respectively.

    System.out.println(
        "xxxxx".replaceAll("x{2,3}", "[x]")
    ); "[x][x]"

    System.out.println(
        "xxxxx".replaceAll("x{2,3}?", "[x]")
    ); "[x][x]x"

Essentially anywhere a * is a repetition metacharacter for "zero-or-more", you can use {...} repetition construct. Note that it's not true the other way around: you can use finite repetition in a lookbehind, but you can't use * because Java doesn't officially support infinite-length lookbehind.

References

• regular-expressions.info/Repetition

Related questions

• Difference between .* and .*? for regex
• regex{n,}? == regex{n}?
• Using explicitly numbered repetition instead of question mark, star and plus
  • Addresses the habit of some people of writing a{1}b{0,1} instead of ab?