Why doesn't .join() work with function arguments?

Question

Why does this work (returns \"one, two, three\"):

var words = [\'one\', \'two\', \'three\'];
$(\"#main\").append(\'
\' + words.join(\", \") + \'         


        

Answer 1

If you are not interested on other Array.prototype methods, and you want simply to use join, you can invoke it directly, without converting it to an array:

var displayIt = function() {
    return 'the list: ' + Array.prototype.join.call(arguments, ',');
};

Also you might find useful to know that the comma is the default separator, if you don't define a separator, by spec the comma will be used.