What is the best/fastest way to convert CMSampleBufferRef to OpenCV IplImage?

Question

I am writing an iPhone app that does some sort of real-time image detection with OpenCV. What is the best way to convert a CMSampleBufferRef image from the camera

Answer 1

This sample code is based on Apple's sample to manage CMSampleBuffer's pointer:

- (IplImage *)createIplImageFromSampleBuffer:(CMSampleBufferRef)sampleBuffer {
    IplImage *iplimage = 0;
    if (sampleBuffer) {
        CVImageBufferRef imageBuffer = CMSampleBufferGetImageBuffer(sampleBuffer);
        CVPixelBufferLockBaseAddress(imageBuffer, 0);

        // get information of the image in the buffer
        uint8_t *bufferBaseAddress = (uint8_t *)CVPixelBufferGetBaseAddressOfPlane(imageBuffer, 0);
        size_t bufferWidth = CVPixelBufferGetWidth(imageBuffer);
        size_t bufferHeight = CVPixelBufferGetHeight(imageBuffer);

        // create IplImage
        if (bufferBaseAddress) {
            iplimage = cvCreateImage(cvSize(bufferWidth, bufferHeight), IPL_DEPTH_8U, 4);
            iplimage->imageData = (char*)bufferBaseAddress;
        }

        // release memory
        CVPixelBufferUnlockBaseAddress(imageBuffer, 0);
    }
    else
        DLog(@"No sampleBuffer!!");

    return iplimage;
}

You need to create a 4-channel IplImage because the Phone's camera buffer is in BGRA.

To my experience, this conversion is fast enough to be done in a real-time application, but of course, anything you will add to it will cost time, especially with OpenCV.