Bootstrapping a web server in Scala

Question

The following is possible using Python:

$ apt-get install python
$ easy_install Flask
$ cat > hello.py
from flask import Flask
app = Flask(__name__)

@app.rou         


        

Answer 1

You could use an embedded Jetty Server:

/*
 * Required Libs: Jetty, Servlet API
 *
 * Compile:
 *   scalac -cp jetty-6.1.14.jar:jetty-util-6.1.14.jar:servlet-api-2.5-6.1.14.jar WebServer.scala
 *
 * Run:
 *  scala -cp .:jetty-6.1.14.jar:jetty-util-6.1.14.jar:servlet-api-2.5-6.1.14.jar WebServer
 */
import org.mortbay.jetty.Server
import org.mortbay.jetty.servlet.Context
import javax.servlet.http.{HttpServlet,
                       HttpServletRequest, 
                       HttpServletResponse}

class HelloServlet extends HttpServlet {
  override def doGet(req : HttpServletRequest, resp : HttpServletResponse) =
    resp.getWriter().print("Hello There!")
}

object WebServer {
  def main(args: Array[String]) {
    val server = new Server(8080)
    val root = new Context(server, "/", Context.SESSIONS)
    root.addServlet(classOf[HelloServlet], "/*")
    server.start()

    println("Point your browser to http://localhost:8080/")
    println("Type [CTRL]+[C] to quit!")

    Thread.sleep(Long.MaxValue)
  }
}

In case you target for a LOC comparison, You use the HTTP server embedded with the Sun JDK. Another solution could be to use javax.xml.ws.Endpoint and the Provider API.