Deserialize JSON to classes

Question

Server returns such part of JSON:

{\"condition\": {
    \"or\": [
        {
            \"and\": [
                {
                    \"operand\": \"a\",
             


        

Answer 1

You should use a class, not an interface. Otherwise, Jackson cannot create an instance.

I believe you also need to create default (aka no-arg) constructors for your POJOs for Jackson to work.

Also, a good general approach for creating a Jackson mapping is to instantiate a Java instance of your classes and then create the JSON from that, Java -> JSON. This makes it much easier to understand how the mapping is different - going from JSON -> Java is harder to debug.