Is n or nlog(n) better than constant or logarithmic time?

Question

In the Princeton tutorial on Coursera the lecturer explains the common order-of-growth functions that are encountered. He says that linear and linearithmic running times are \"w

Answer 1

Yes constant time i.e. O(1) is better than linear time O(n) because the former is not depending on the input-size of the problem. The order is O(1) > O (logn) > O (n) > O (nlogn). Linear or linearthimic time we strive for because going for O(1) might not be realistic as in every sorting algorithm we atleast need a few comparisons which the professor tries to prove with his decison Tree- comparison analysis where he tries to sort three elements a b c and proves a lower bound of nlogn. Check his "Complexity of Sorting" in the Mergesort lecture.