I was under the impression that it was possible to access data from a sub-node of a linked list or similar structure by using the arrow and dot operators together like so:
Use ->
for pointers; use .
for objects.
In your specific case you want
if (sample->left->num > sample->right->num)
because all of sample
, sample->left
, and sample->right
are pointers.
If you convert any of those pointers in the pointed to object; use .
instead
struct a copyright;
copyright = *(sample->right);
// if (sample->left->num > copyright.num)
if (*(sample->left).num > copyright.num)